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SVEN [57.7K]
3 years ago
13

48.5 is 7 percent of what number

Mathematics
2 answers:
lana [24]3 years ago
7 0
The answer is 692.857143 
Hope this helps! :)
DedPeter [7]3 years ago
4 0

Let's assume

that number as x

we are given

48.5 is 7 percent of x

so, we can write it as

7 % of x =48.5

\frac{7}{100} x=48.5

now, we can solve for x

100*\frac{7}{100} x=48.5*100

7 x=4850

divide both sides by 7

\frac{7x}{7} =\frac{4850}{7}

x=\frac{4850}{7}

x=692.857

so, that number is 692.857.............Answer

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In the last three years frederico's basketball team won 40 more games than they lost if they won 150 games what was their ratio
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150 games won: 110 games lost

Ratios
150:110
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3 0
3 years ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
Match each area to its corresponding radius or diameter of the circle.(All areas are approximate.) )
MA_775_DIABLO [31]

Answer:

<u>Radius: 12 units </u>

  • Area: πr² = 3.14*12² = 452.16 square units

<u>Diameter: 16.8 units</u>

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<u>Radius: 3.4 units</u>

  • Area: πr² = 3.14*3.4² = 452.16 square units  

<u>Diameter: 10 units</u>

  • Area: πd²/4 = 3.14*10²/4 = 78.5 square units
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Answer:

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Step-by-step explanation:

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