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vampirchik [111]
3 years ago
5

I need the answer HELP pls

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

i believe the answer is A ^^

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Please help me with the problem
mixas84 [53]
Let's see what we're working on here 

\frac{1}{2}  - 2(m) =?
            ? = 0
Simplify this → \frac{1}{2}

\frac{1}2y} - 2(m) = ?

\frac{2(m)(2)}{2}

\frac{1 - 4(m)}{2} = ?

\frac{1 - 4(m)}{2} = 2

-4(m) + 1 = 0
 Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1 
Multiply( ×) the number -1 to your sides for this part of the equation 

Therefore, the value of m is \frac{1}{4}
m =  \frac{1}{4}


3 0
4 years ago
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There are 500 sheet of paper in the pack Hannah bought. She has used 137 sheets already. How many sheets of paper does Hannah ha
Grace [21]
Just work out 500 takeaway 137
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3 years ago
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What is the domain of the function shown
Sedaia [141]
It would be choice b.
The domain is the range of x values which in this case is from -5 to 3.
4 0
3 years ago
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How does the Moon reflect sunlight as it orbits Earth, creating predictable<br>cyclic patterns?​
kogti [31]
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4 0
3 years ago
A room with poor air quality has a particle concentration of 80 units. ​A fan removes 50% of the remaining particles each hour.
Eddi Din [679]

Answer:

20 units

Step-by-step explanation:

Initial particle concentration = 80 units

Particles removed each hour = 50% of the remaining particles

To find:

Particle concentration after 2 hours = ?

Solution:

Particles removed in 1 hour = 50% of remaining particles

i.e. Particles removed in 1 hour = 50% of initial concentration

Particles removed in 1 hour = 50% of 80 = 40

Particles removed in next 1 hour = 50% of remaining particles

i.e. Particles removed in next 1 hour = 50% of concentration after 1 hour

Particles removed in next 1 hour = 50% of 40 = 20

Total particles concentration removed in 2 hours = 40 + 20 = 60 units

Therefore, particle concentration after 2 hours = Initial concentration - Total particle concentration removed in 2 hours

= 80 - 60 = <em>20 units</em>

8 0
3 years ago
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