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3 years ago

Evaluate y=x+5 when y=10.

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

Step-by-step explanation:

Subtract 5 to both sides when plugging in 10 for y.

$10=x+5 \\-5 -5$ ⇒ $5=x$

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I really need help this is hard

Elis [28]

Answer:

it's simple

Step-by-step explanation:

r=d/2

r=12/2

r=6

circumference of circle = 2πr

=2*(3.14)*6

=12*3.14

= 37.68

8 0

3 years ago

Ma= P2-P1/t solve for p1

natulia [17]

Answer:

P1 = P2 - ma*t

Step-by-step explanation:

ma= P2-P1/t

we multiply by t both sides of the equation

ma*t = (P2 - P1)*t/t

ma*t = P2 - P1

we sum by P1 both sides of the equation:

P1 +ma*t = P2 - P1 +P1

We ave:

P1 + ma*t = P2

we subtract by ma*t both sides of the equation:

P1 + ma*t -ma*t = P2 - ma*t

finally we have:

P1 = P2 - ma*t

3 0

3 years ago

An experiment is set up to study the weights of 35 mice after they are injected with a drug. The population mean is 23.50 grams

IgorC [24]

Answer:

The standard error of the sample mean is 0.57

Step-by-step explanation:

we know that

The Standard Error Formula is given by the formula

$SE = \frac{s}{ \sqrt{n} }}$

where:

SE = standard error

s = standard deviation

n = the sample size

In this problem we have

$s=3.40\ g\\n=35$

substitute in the formula

$SE = \frac{3.40}{ \sqrt{35}}}$

$SE=0.57$

6 0

3 years ago

(15 points) Complete the inequality. (-1/9)(3/5) __ - 2/15

mario62 [17]

Step-by-step explanation:

-1/9 × 3/5 = -1/15

-1/15>-2/15

3 0

3 years ago

Read 2 more answers

Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 12 h using both

Leokris [45]

Answer:

Jim's hose: 27 hours.

Bob's hose: 21.6 hours.

Step-by-step explanation:

Let t represent hours taken by Jim's hose.

Part of pool filled by Jim's hose in 1 hour would be $\frac{1}{t}$ .

We have been given that Bob's hose, used alone, takes 20% less time than Jim's hose alone. This means that Bob's hose take will take 80% time of Jim's hose that is $0.8t$ .

Part of pool filled by Bob's hose in 1 hour would be $\frac{1}{0.8t}$ .

We are also told that it takes 12 hours using both hoses. Part of pool filled by both hoses in 1 hour would be $\frac{1}{12}$ .

Now, we will add rates of both hoses and equate with $\frac{1}{12}$ as:

$\frac{1}{t}+\frac{1}{0.8t}=\frac{1}{12}$

$\frac{0.8}{0.8t}+\frac{1}{0.8t}=\frac{1}{12}$

$\frac{0.8+1}{0.8t}=\frac{1}{12}$

$\frac{1.8}{0.8t}=\frac{1}{12}$

Cross multiply:

$0.8t*1=1.8(12)$

$0.8t=21.6$

$\frac{0.8t}{0.8}=\frac{21.6}{0.8}$

$t=27$

Therefore, it will take 27 hours for Jim's hose to fill the pool alone.

Time take by Jim's hose alone: $0.8t\Rightarrow 0.8(27)=21.6$ .

Therefore, it will take 21.6 hours for Bob's hose to fill the pool alone.

3 0

4 years ago