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wel
3 years ago
15

Who set up their equation correctly for the following question?

Mathematics
2 answers:
morpeh [17]3 years ago
7 0
Im not sure but i think it is morgan
mixer [17]3 years ago
6 0

Answer:

Morgan is the correct answer.

Step-by-step explanation:

See it cant be kelly or miles and it wouldnt  make sense for Esmeralda.

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Halppppppppppppppppppp​
Hatshy [7]

Answer:

Yes

Step-by-step explanation:

y\leq 3x+9\\\\8\leq 3(7)+9\\\\8\leq 21+9\\\\8\leq 30

Yes, the given point makes the inequality true. We end up with a true statement.

Hope this helps.

4 0
3 years ago
SOMEONE HELP ME PLSSSSSSS
mr Goodwill [35]

Answer:

y = 8x

Step-by-step explanation:

hope this is what u need if not comment and I'll change it

<3

7 0
3 years ago
3 1/2-2/3 help plz its fraction and Idgaf to understand xd
Hatshy [7]

Answer:

2 5/6

Step-by-step explanation:

WE CHANGE 3 1/2 INTO IMPROPER FRACTION WHICH IS 7/2

7/2-2/3=2 5/6

8 0
3 years ago
Read 2 more answers
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
4 years ago
Can anyone help me with jest ions 3 and 4
wolverine [178]
Cylinder
volume<span>=</span><span>π</span><span>r^</span><span>2</span><span>h
</span>
8 0
3 years ago
Read 2 more answers
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