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patriot [66]
3 years ago
14

To find the product of 42.12 and 10³, move the decimal point in 42.12 __ places to the right because 10³ has __ zeros.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0
<h3>To find the product of 42.12 and 10^3,  move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>

<em><u>Solution:</u></em>

Given that,

\text{ product of } 42.12 \text{ and } 10^3

Which means,

42.12 \times 10^3

Here, the exponent of 10 is positive ( which is 3)

When the exponent is positive, we have to move the decimal point to right

When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10

Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12

Therefore,

42.12 \times 10^3 = 42120

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Hello I need help on this question!
Sloan [31]

Answer:

5

Step-by-step explanation:

Refer to attachment for marking of sides.

In the given figure , ∆ABC , ∆ABD and ∆ADC are right angled triangles . Therefore here we can use the Pythagoras theorem , as ,

\longrightarrow base² + perpendicular² = hypotenuse ² .

<u>•</u><u> </u><u>In </u><u>∆</u><u>A</u><u>B</u><u>D</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>

\longrightarrow AB² + BD² = AD²

\longrightarrow AB² + x² = 10²

\longrightarrow AB² = 10² - x²

\longrightarrow AB² = 100 - x²

\rule{200}2

<u>•</u><u> </u><u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>D</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>

\longrightarrow AC² + AD² = CD²

\longrightarrow AC² = 20² - 10²

\longrightarrow AC² = 400 - 100

\longrightarrow AC² = 300

\rule{200}2

<u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>B</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>,</u>

\longrightarrow AC² = AB² + BC²

Substituting the values from above ,

\longrightarrow 300 = 100-x² + (20-x)²

\longrightarrow 300 = 100 - x² + 400 + x² - 40x

\longrightarrow 40x = 500 - 300

\longrightarrow 40x = 200

\longrightarrow x = 200/40

\longrightarrow x = 5

<h3>Hence the required answer is 5 .</h3>

8 0
2 years ago
Ling is 1 year less than twice as old as his sister. If the sum of their ages is 14 years how old is Ling
SashulF [63]
<span>Sister is  5 </span>
<span>Yan Ling is 9 </span>
<span>9+5=14 </span>
<span>1 less than twice 5 is 9.</span>
7 0
3 years ago
HELP?!? idk what im doing and nobody has asked this. will give brainliest answrr or whatever its called.
Illusion [34]

9514 1404 393

Answer:

  \textbf{A.   }x=\dfrac{-4\pm2\sqrt{13}}{3}

Step-by-step explanation:

First of all, subtract 12 from both sides of the equation to put it into standard form:

  3x² +8x -12 = 0

Then identify the a, b, c of this form:

  ax² +bx +c = 0

You see that a=3, b=8, c=-12.

Now use those values in the quadratic formula for the solutions:

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-8\pm\sqrt{8^2-4(3)(-12)}}{2(3)}\\\\x=\dfrac{-8\pm\sqrt{208}}{6}=\dfrac{-8\pm4\sqrt{13}}{6}\\\\\boxed{x=\dfrac{-4\pm2\sqrt{13}}{3}}\qquad\text{factor 2 from numerator and denominator}

6 0
3 years ago
The length of a rectangle is 2 ft longer than its width.
notsponge [240]
If the length is 2ft longer than it’s width
Let’s assume width as X and so the length will be X+2
Perimeter=40ft
Putting the values into a equation, we get,
X+2+X=40
=2X+2=40
=2X=38
=X=19
Therefore
Length =X+2=19+2
=21ft
Width=X=19ft
Area of rectangle =lxb
= 21x19
3992ft
HOPE IT WAS HELPFUL :)
6 0
3 years ago
Pls help me on this, I need to know about the expressions and pictures
saul85 [17]
Start by expanding the brackets "2(x+4)". Then, start collecting similar terms (those that have "x" with each other, and those that dont have "x" go together). Finally, your answer should be "3x + 5 - 2x - 8 + 3" which is equal to just x.
6 0
3 years ago
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