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patriot [66]
3 years ago
14

To find the product of 42.12 and 10³, move the decimal point in 42.12 __ places to the right because 10³ has __ zeros.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0
<h3>To find the product of 42.12 and 10^3,  move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>

<em><u>Solution:</u></em>

Given that,

\text{ product of } 42.12 \text{ and } 10^3

Which means,

42.12 \times 10^3

Here, the exponent of 10 is positive ( which is 3)

When the exponent is positive, we have to move the decimal point to right

When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10

Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12

Therefore,

42.12 \times 10^3 = 42120

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8 0
3 years ago
Read 2 more answers
Simplify the following using PEMDAS: [3−(3⋅3)+33÷3] × 4⋅5/10−2⋅3
kompoz [17]

Answer: 34

Step-by-step explanation:

<u>Given expression</u>

[3 - (3 · 3) + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by parentheses in the bracket</u>

=[3 - 9 + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by multiplication</u>

=[3 - 9 + 33 ÷ 3] × 20 / 10 - 6

<u>Simplify by division</u>

=[3 - 9 + 11] × 10 - 6

<u>Simplify by bracket (addition/subtraction)</u>

=[-6 + 11] × 10 - 6

=[4] × 10 - 6

<u>Simplify by multiplication</u>

=40 - 6

<u>Simplify by subtraction</u>

=\boxed{34}

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
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