-6r+5
the two like terms are the ones with R. combine -4r and -2r to get -6r
Answer:
d
Step-by-step explanation:
Answer: 
Step-by-step explanation:

Add
on both sides and subtract
on both sides to leave x's on the left side and independent values on the right.


Solve the fractions.





Convert the mixed fraction
to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.




Answer:
See below
Step-by-step explanation:


If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.