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3 years ago

9

HELP ME PLEASE QUICK QUICK QUICK

2 answers:

Musya8 [376]3 years ago

7 0

B(-7,10) is the answer

vovikov84 [41]3 years ago

4 0

Answer:

The answer is B-(-7,10)

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A swimming pool fence was placed around a rectangular enclosure of length 12 m and width 8 m. A post was placed every 2 m. How m

eimsori [14]

P = 2(L + W)
P = 2(12 + 8)
P = 2(20)
P = 40.....so there is 40 meters of fence around the pool. If a post was placed every 2 meters, then u would have (40 / 2) = 20 posts <=

5 0

4 years ago

Pls help me prove this

Levart [38]

Parallel lines

Lines that are always at a given distance from each other and never cross, is called the "parallel" line.

If a diagonal line (PS) interrupts two parallel lines and gives them equal angles, can say that these two lines are parallel. Because the angles are opposite to the vertex and has it opposite angles with other angle

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3 years ago

Joaquin recorded a temperature of 62*F this morning for science class.The temperature increased 61/2*F In the afternoon before d

masha68 [24]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

In the right ∆ABC, the hypotenuse AB = 17 cm. M is the midpoint of the hypotenuse. Find the legs if PAMC=32 cm and PBMC=25 cm

jeyben [28]

Answer:

The length of the legs is 8.64cm and 14.64cm respectively

Step-by-step explanation:

I've added an attachment to aid my explanation.

At different intervals, I'll be making reference to it.

Given

$AB = 17$

$PAMC = 32$

$PBMC = 25$

From the attachment, we have:

$y + z = AB$

Since, M is the Midpoint

$y = z = \½AB$

Substitute 17 for AB

$y = z = \½ * 17$

$y = z = 8.5$

Also, from the attachment

$v + x + z = PAMC$

$v + x + y = 32$

Substitute 8.5 for y

$v + x + 8.5 = 32$

$v + x = 32 - 8.5$

$v + x = 23.5$ --------- (1)

Also, from the attachment

$v + w + z = 25$

Substitute 8.5 for z

$v + w + 8.5 = 25$

$v + w = 25 - 8.5$

$v + w = 17.5$ ----------- (2)

Subtract (2) from (1)

$v - v + x - w = 23.5 - 17.5$

$x - w = 6$

Make x the subject

$x = 6 + w$

Apply Pythagoras Theorem:

We have that:

$AB^2 = AC^2 + BC^2$

The above can be replaced with

$17^2 = x^2 + w^2$ (see attachment)

$289 = x^2 + w^2$

Substitute 6 + w for x

$289 = (6 + w)^2 + w^2$

$289 = 36 + 12w + w^2 + w^2$

$289 - 36 = 12w + 2w^2$

$253 = 12w + 2w^2$

Reorder

$2w^2 + 12w - 253 = 0$

Solve using quadratic equation:

$w = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 2$

$b = 12$

$c = -253$

$w = \frac{-12 \± \sqrt{12^2 - 4 * 2 * -253}}{2 * 2}$

$w = \frac{-12 \± \sqrt{144 + 2024}}{4}$

$w = \frac{-12 \± \sqrt{2168}}{4}$

$w = \frac{-12 \± 46.56}{4}$

Split:

$w = \frac{-12 + 46.56}{4}$ or $w = \frac{-12 - 46.56}{4}$

$w = \frac{34.56}{4}$ or $w = \frac{-58.56}{4}$

$w = 8.64$ or $w = -14.64$

But length can't be negative

So:

$w = 8.64$

Recall that: $x = 6 + w$

$x = 6 + 8.64$

$x = 14.64$

<em>Hence, the length of the legs is 8.64cm and 14.64cm respectively</em>

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3 years ago

A line segment has endpoints at (1, 3) and (3, 1). If the line segment

weeeeeb [17]

Second point would be at (5,3)

4 0

3 years ago

Read 2 more answers