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3 years ago

HELP PLZ PLZ ITS DUE IN 30 MINUTES

Mathematics

1 answer:

Bad White [126]3 years ago

3 0

Answer:

wouldn't that be...24x²?

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Find the values of x and y. 107<br> X= y=

Debora [2.8K]

Answer:

y= 73 degrees

x=34 degrees

Step-by-step explanation:

180-107=73

y= 73 degrees

73+73= 146

180-146=34

x=34 degrees

8 0

3 years ago

The flag of a country contains an isosceles triangle. (Recall that an isosceles triangle contains two angles with the same mea

Mrac [35]

Let us start with the unknown. Let us give one of the base angles the value of x. The other base angle is also x since both the base angles in an isosceles triangle will be equal. The remaining angle is 40 more than three times one of the base angles.It is 3x + 40. Here we get the equation

x+x+3x+40=180

5x + 40 = 180

5x = 180 - 40 = 140

Therefore x = 140/5 = 28

So the angles are 28, 28 and 124.

The third angle is 3 times 28 + 40 = 84 + 40 = 124.

5 0

3 years ago

For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f

Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0$

We want to find $f$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)$

$\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C$

$\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)$

$\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C$

$\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0$

so $\vec F$ is not conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)$

$\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)$

$\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C$

$\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}$

so $\vec F$ is conservative.

4 0

3 years ago

The length of a screw produced by a machine is normally distributed with a mean of 0.65 inches and a standard deviation of 0.01

Makovka662 [10]

Notice it is +/-4 times standard deviation (0.65-0.04 = 0.61, 0.69-0.04=0.65)

That's almost everything. So (D) is the answer.
<span>99.993666</span>%

3 0

3 years ago

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Please help me :( A standard six-sided die is rolled. What is the probability that it is not a 4?

zmey [24]

Answer:

The answer is 5/6, or .833, 3 repeated.

Step-by-step explanation:

The 4 is only one side of the die, or 1/6 if the surface of the die. So the other part that is left is the other 5/6 of the surface.

6 0

2 years ago

Read 2 more answers