The formula is
A=p (1+rt)
A cost of the car 13080
P amount deposited 12000
R interest rate 0.03
T time?
Solve for t
T=[(A/p)-1]÷r
T=((13,080÷12,000)−1)÷0.03
T=3 years
Answer:
A =
- B
Step-by-step explanation:
Given
R = x(A + B) ← divide both sides by x
= A + B ( subtract B from both sides )
- B = A
X+2y=8
2y=8/2y
=4 is the answer. You’re so welcome
1st year= 18000 x 0.85 = 15300
2nd year= 15300 x 0.85 = 13005
3rd year= 13005 x 0.85= 11054.25