All categories

4 years ago

483 is what part of 121?

2 answers:

5 0

Since 483 is larger than 121, the correct answer is a whole number with a fraction:

483/121 = 3.991, or about 4. "483 is approx. four times 121."

Nadusha1986 [10]4 years ago

5 0

Answer:

yes, since 483 is greater than 121, the correct answer is a whole number with a fraction:

483/121 = 3.991, or about 4. "483 is approx. four times 121."

You might be interested in

Find the value of the following expression

Misha Larkins [42]

Looks like the expression is

(2⁸ • 5⁻⁵ • 19⁰) • (5⁻² / 2³)⁴ • 2²⁸

First, any positive number raised to 0 is 1:

(2⁸ • 5⁻⁵ • 1) • (5⁻² / 2³)⁴ • 2²⁸

(2⁸ • 5⁻⁵) • (5⁻² / 2³)⁴ • 2²⁸

Exponents in a denominator can be rewritten as negative exponents in the numerator:

(2⁸ • 5⁻⁵) • (5⁻² • 2⁻³)⁴ • 2²⁸

Distribute the 4th power across the product 5⁻² • 2⁻³ :

(5⁻² • 2⁻³)⁴ = 5⁻⁸ • 2⁻¹²

so we have

(2⁸ • 5⁻⁵) • (5⁻⁸ • 2⁻¹²) • 2²⁸

Multiplication is associative, so we can ignore the parentheses. Combine factors with equal bases and simplify the exponents:

2⁸ • 5⁻⁵ • 5⁻⁸ • 2⁻¹² • 2²⁸

2⁸⁻¹²⁺²⁸ • 5⁻⁵⁻⁸

2²⁴ • 5⁻¹³

Rewrite the negative exponent as a positive one:

2²⁴ / 5¹³

6 0

3 years ago

For circle C, CG = CE, CG is perpendicular to FB, and CE is perpendicular to DA. What conclusion can be made? a circle with cent

svetlana [45]

Answer:

A circle with center C has chords FB and DA which are equidistant from C.

Step-by-step explanation:

A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.

From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.

Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.

8 0

3 years ago

The function ggg models the number of mosquitoes (in millions of mosquitoes) in a certain area as a function of rainfall (in cen

melomori [17]

Answer:

(Choice A) A More rainfall relates to more mosquitoes, as long as rainfall is less than 2 cm²

Step-by-step explanation:

The given function for the number of mosquitoes, (by analysis of the options) is, g(x) = 4·x - x²

Where;

x = The amount of rainfall

g(x) = The number of mosquitoes in millions

The given function can be expressed as follows;

g(x) = 4·x - x² + 0

The maximum point is given by g'(x) = d(4·x - x²)/dx = 4 - 2·x = 0

At the maximum (turning point), we have;

4 - 2·x = 0

4 = 2·x

x = 4/2 = 2

The level of rainfall that gives the maximum number of mosquitoes is, x = 2 cm²

The number of mosquitoes increases from zero rainfall up to the maximum number of 4 million mosquitoes at 2 cm² rainfall and then decreases to zero as the rainfall increases further more than 2 cm², as shown in the attached graph of the function g(x) that models the number of mosquitoes created with MS Excel

Therefore, the true statement is (Choice A) more rainfall relates to more mosquitoes, as long as (the level of) rainfall is less than (the maximum) 2 cm².