Answer:
The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )
Step-by-step explanation:
Given equation as :
3 x² + 6 x +15 = 0
The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as
x =
So , from given eq , the value of x is now obtain as
x =
Or, x =
Or, x =
∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )
Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer
The only root is -2. The roots are where the function goes through the x-axis. This polynomial goes through in lots of places, but the only answer that matches is -2
now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5Cdotfill%20%26%20%5C%244000%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B18%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%204000%3DP%5B1%2B%280.05%29%28%5Cfrac%7B3%7D%7B2%7D%29%5D%5Cimplies%204000%3DP%281.075%29%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B4000%7D%7B1.075%7D%3DP%5Cimplies%203720.93%5Capprox%20P)
Let me use Python to find the answers
Program.

![\tt Prices=[75,120,120,145,150,150,150,175,175,200,225,275]](https://tex.z-dn.net/?f=%5Ctt%20Prices%3D%5B75%2C120%2C120%2C145%2C150%2C150%2C150%2C175%2C175%2C200%2C225%2C275%5D)



Output:;
- Mean=163.333
- Median=150.0
- Mode=150
Console attached