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Readme [11.4K]
3 years ago
5

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

dy/dx = [1/ln(10)][(2x+6)/(x^2 +6x)]

Step-by-step explanation:

See attachment

WARRIOR [948]3 years ago
3 0

Answer:

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

Step-by-step explanation:

given

y = \log_{10}{(x^2+6x)}

using the property of log \log_ab=\frac{log_cb}{log_ca}, and if c =e,\log_ab=\frac{ln{b}}{ln{a}}, we can rewrite our function as:

y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}

now we can easily differentiate:

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

This is our answer!

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Read 2 more answers
4. Divide z(5z2 - 80) by 5z (z+4)​
insens350 [35]

Answer:

z-4

Step-by-step explanation:

z(5z²-80) ÷ 5z(z+4) = z-4

Step-by-step explanation:

Given: z(5z²-80) ÷ 5z(z+4)

Calculation:

First we factor numerator z(5z²-80)

Take out 5 from 5z²-80 and we get 5z(z²-16)

Now we factor 16 = 4²

5z(z²-4²)

Using formula, (a²- b²)=(a+b)(a-b)

5z(z²- 4²)⇒5z(z+4)(z-4)

Simplified fraction

5z(z+4)(z-4) ÷ 5z(z+4)

Cancel like factor from numerator and denominator

⇒ z-4

Thus, z(5z²-80) ÷ 5z(z+4) = z-4

5 0
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