Question

Fine the 25th term of an arithmetic progression 12,16,20,24,​

Answer 1

Answer:

108

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 12 and d = 16 - 12 = 4, thus

$a_{25}$ = 12 + (24 × 4) = 12 + 96 = 108

Answer 2

108. As you can see, it is going up by 4 each time. So 12 being the 1st term, 16 being the 2nd, and so on. Keep adding 4 until you reach the 25th term, which is 108