All categories

2 years ago

I need answers for number 20 I need This done by Tuesday

Mathematics

1 answer:

nikdorinn [45]2 years ago

6 0

One ticket costs $24.50 - $19 more for evening

Six tickets cost 6 ( $24.50 - $19 ) more

Answer: 6 ( $24.50 - $19 )

Problem 18 is D by the way

You might be interested in

Write an integer for this situation: a profit of $12

finlep [7]

Answer:

+12

Step-by-step explanation:

3 0

2 years ago

1/2×1/3×1/4 need to show work

klasskru [66]

1x1x1=1
2x3x4=6x4=24
1/24
please mark me brainliest I'm trying to level up

3 0

2 years ago

Read 2 more answers

10lb bag of potatoes or $5.50 or 15lb bag of potatoes for $8.40 which is a better deal

Jobisdone [24]

15lbs is a better deal

6 0

2 years ago

*Will mark Brainliest (10 points)* Please explain, thanks!

MAVERICK [17]

Standard form Ax + By = C
so
(y - y1) = m(x - x1)
given (5, -7) and m = -1/5
so
y + 7 = -1/5(x - 5)
-5y - 35 = x - 5
x + 5y = -30

answer
d. x + 5y = -30

5 0

2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago