The square root of 25 would be 5!
Brainliest please? I am trying to get my rank to ace!
For 4x^2y over 2x^8y^4 try 2 over x^6y^3
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
t α 1 /r ; t = k/r
Step-by-step explanation:
Given that :
Time taken, t varies inverse as rate, r
MATHEMATICALLY,
t α 1 /r
Hence,
t = k/r ;
Where, k is the proportionality constant
Hence, the situation could be expressed as :
t = k/r OR
t α 1 /r
Answer:
<em>well non of the answer choices are exact but i would say a/the first one. im not sure but they should add up to about 7.65%.</em>
Step-by-step explanation:
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