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3 years ago

Which equation is an equation of a circle with a radius of 3 and it’s center is at (5,-2)?

1 answer:

5 0

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{5}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[1em] [x-5]^2+[y-(-2)]^2=3^2\implies (x-5)^2+(y+2)^2=9$

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Kruka [31]

Answer:

$\frac{1}{5}$ is the answer

Step-by-step explanation:

$h(x)=\frac{x+3}{5} \\$

Substituting the -2 in place x

Therefore , h(-2) :

$\frac{(-2)+3}{5} \\\frac{-2+3}{5}\\\frac{1}{5}$

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Answer:

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2 years ago

Which step should be completed first in the following problem 4(27÷3²)

Yakvenalex [24]

Answer:

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3 years ago

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