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4 years ago

What keyword do we use when instantiating an object _________________

Computers and Technology

1 answer:

fgiga [73]4 years ago

8 0

Answer:

The correct answer for the given question is option(c) i.e new

Explanation:

Instantiating an object means creating a object or creating a instance of a class .

The new keyword allocates a memory for the object .

To create instance we follow following syntax

classname objectname =new classname();

for example

abc ob=new abc();

here abc is a class and ob is an object for that class with the help of new keyword it allocate the memory for the object ob.

create, =,object ,is are not any keyword to instantiating an object.

so the correct answer is " new "

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Output each floating-point value with two digits after the decimal point, which can be achieved as follows:

sdas [7]

Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

paint_needed = area/350.0

print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

3 0

3 years ago

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac

GREYUIT [131]

Answer:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int inputYear;

boolean isLeapYear;

isLeapYear = false;

inputYear = scnr.nextInt();

// If a year is divisible by 400, then it is a leap year

if (inputYear % 400 == 0)

isLeapYear = true;

// If a year is divisible by 100, then it is not a leap year

if (inputYear % 100 == 0)

isLeapYear = false;

// If a year is divisible by 4, then it is a leap year

if (inputYear % 4 == 0)

isLeapYear = true;

if(isLeapYear)

System.out.println(inputYear + " is a leap year.");

else

System.out.println(inputYear + " is not a leap year.");

}

Explanation:

Take the year as an input from user and store it to inputYear variable.
If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.

Output:

1712

1712 is a leap year.

4 0

4 years ago

Read 2 more answers

I still need help, thank you! Will give Brainliest

wlad13 [49]

Answer: 1 what do u think to help u

6 0

3 years ago

A spreadsheet has some values entered: Cell A1 contains 10, cell A2 contains 14, cell A3 contains 7. You enter in cell A4 the fo