Answer:
1st blank: four nitrogenous bases each. (cytosine, adenine, and guanine)
2nd blank: DNA had thymine
3rd blank: RNA has uracil
Answer:
Fertilization
Explanation:
Egg and sperm are cells known as gametes produced by the GAMETOPHYTE of a sexually-reproducing organism via meiosis. Since egg and sperm cells are produced through meiotic division, their chromosomal number is reduced by half of the parental organism. Hence, sperms and eggs are haploid cells (n) produced by a diploid organism (2n).
Sperm is the male gamete while egg is the female gamete. These two haploid gametes fuse in a process called FERTILIZATION, to produce a diploid ZYGOTE that eventually grows into the diploid structure of the organism called SPOROPHYTE. This system of reproduction called ALTERNATION OF GENERATIONS is used by lower and higher plants.
All but 3 because it only contains 1 carbon atom
Enter stationary phase of the bacterial growth curve. The rate of death of the bacteria is equaled by
the rate of replication. This is due to the stiff competition of the individuals
for the scarce nutrients. The bacteria begin to produce inhibitory molecules that also
increase the rate of mutations among the bacteria due to the harsh environment.
Answer: If a husband and wife who are both carriers of the sickle-cell anemia allele (Ss) but do not have the disease decide to have a child, the offspring can be Normal (SS), carrier (Ss) or sick (ss) with the probability ¼, 2/4 (½) and ¼ respectively.
Explanation: If the mother contributes the dominant allele and the father also contributes the dominant allele, the genotype of the child will be SS. The probability is ¼. This means there is a 25% chance that a randomly selected offspring will be a normal child and will not have sickle-cell anemia.
If the mother contributes the dominant allele and the father contributes the recessive allele, the genotype of the child will be Ss. The probability is 2/4 or ½. This means there is a 50% chance that a randomly selected offspring will be a carrier of sickle cell anemia, but will not have sickle-cell anemia.
If the mother contributes the recessive allele and the father also contributes the recessive allele, the genotype of the child will be ss. The probability is ¼. This means there is a 25% chance that a randomly selected offspring will have sickle cell anemia.
Check attached image for illustrations.