Pick 1: 3 apples out of 11 pieces of fruit → 3/11
Pick 2: 4 oranges out of 10 pieces of fruit → 4/10 = 2/5
Pick 1 AND Pick 2
3/11 x 2/5 = 6/55
f(x) = 2x + 1; Paren graph = x;
The graph was shifted one unit up and stretched 2 times.
g(x) = -8(x+4) - 1 = -8x - 32 - 1 = -8x - 33
The graph was shifted 33 units down and stretched 8 times and flipped 180 degrees.
Answer:
Apple
Orange
Step-by-step explanation:
Apple has the greater median with a median value of 150 which is more than that of orange at 130
The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.
Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.
I'm pretty sure that you answered it correctly. 10-U
