41/6×1^2 this is confusing

Mathematics

1 answer:

trasher [3.6K]2 years ago

5 0

6.83 with the 3 repeating
41 / 6 = 6.8333...
1^2 = 1
6.83 x 1 = 6.83

You might be interested in

The athletic departments at 10 randomly selected U.S. universities were asked by the Equal Employment Opportunity Commission to

Lesechka [4]

Answer: Mean = 3.5 , median = 2.5, mode = 2, geometric mean = 2.74

Median is the most appropriate measure of central tendency.

The least appropriate = mean

Yes there is an outlier.

Step-by-step explanation:

Given responses : 5, 4, 2, 1, 1, 2, 10, 2, 3, 5.

First arrange them in increasing order, $\sqrt[10]{1\times1\times2\times2\times2\times3\times4\times5\times5\times10 }\\\\=\sqrt[10]{24000} \approx2.74$

Its sum = 35

Mean of n observations = (Sum of observations) ÷ n

Mean = (35) ÷ 10

=3.5

Here n =10 (even)

Median = average of middle most numbers = $\dfrac{2+3}{2}=\dfrac52=2.5$

Mode = most repeated number = 2 (thrice)

geometric mean = $\sqrt[n]{x_1\times x_2\times.... x_n}$

10 is an outlier as it is very large as compare to other numbers.

When outlier is present in data , the median is the most appropriate measure of central tendency.

Mean affected badly by the outlier so it the least appropriate.

4 0

3 years ago

Ponderosa Paint and Glass carries three brands of paint. A customer wants to buy another gallon of paint to match paint she purc

sveta [45]

Answer:

$\frac{4}{9}$

Step-by-step explanation:

Two events are independent of each other, this is called Compound Probability. Classical example is if two coins are filped, what is the probability of getting two heads in a row.?

Answer: each has 50% probability because there are two states only, either H or T. since we have two coins the probability of getting two heads in row is the product of obtaining heads for each individual coin (which is independent of each other). or is $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$ = 25%. (Notice!).

Back to our problem, now here we have 3 paint brands and one of them is the right paint brand and two of them are not correct brands. so the prabablity that the customer has picked not correct brand is $\frac{2}{3}$ and her husband has not picked correct brand is also $\frac{2}{3}$ , since two probabilities are compound probabilities i.e indepandant of each other the probablity that both woman and her husband fail get correct brand is the product of the two and is = $\frac{2}{3}$ × $\frac{2}{3}$ = $\frac{4}{9}$ .