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3 years ago

12

Mrs. Jones surveys her class of 20 students about their siblings. In the class, 15 have a brother, 16 have a sister, and 12 have

both a brother and a sister. What is the probability that a student has a brother OR a sister?

2 answers:

ryzh [129]3 years ago

5 0

P(Brother or Sister) = .75 + .82 - .65 P(Brother or Sister) = .92 = 92% The reason you subtract the .65 is that scenario does not fit the rule. The rule is the probability of having a brother OR a sister. The .65 represents the kids who have both not either.

Masteriza [31]3 years ago

4 0

About 10 % of people might have a brother or sister

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Please help with number 10 please

lozanna [386]

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3 years ago

Let C = C1 + C2 where C1 is the quarter circle x^2+y^2=4, z=0,from (0,2,0) to (2,0,0), and where C2 is the line segment from (2,

trapecia [35]

Not much can be done without knowing what $\mathbf F(x,y,z)$ is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

$C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)$
$C_2:\mathbf r_2(t_2)=(1-t_2)(2,0,0)+t_2(3,3,3)=(2+t_2, 3t_2, 3t_2)$

where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

$\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
$\mathrm d\mathbf r_2=(1,3,3)\,\mathrm dt_2$

and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
$=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
${}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2$

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3 years ago

How to simplify 80/7

Korolek [52]

Answer:

$11 \frac{3}{7}$

Step-by-step explanation:

80 divided by 7 is 11 with a remainder of 3.

7 0

3 years ago

Read 2 more answers

What is the average score of runa 140,96 and 13?

scoundrel [369]

$\huge\textsf{Hey there!}$

$\large\textsf{Formula:}$

$\mathsf{\dfrac{Sum\ of\ all\ terms}{Total\ number\ of\ values\ in\ the\ data}= your\ mean/average}$

$\mathsf{\dfrac{140+96+13}{3}}$

$\mathsf{140+36+13}$

$\mathsf{140 + 96 = \bf 236}$

$\mathsf{236 + 13}$

$\mathsf{ = \bf 249}$

$\mathsf{\dfrac{249}{3}}$

$\mathsf{= \bf 83}$

$\boxed{\boxed{\large\textsf{Possible answer: \huge \bf 83}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago

I neeed help plz 30 points

Mice21 [21]

Answer:

Step-by-step explanation:

NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2

AT = √[(8 - 1 )² + (1 - 2)²] = 5√2

TS = √[(3 - 8 )² + (- 4 - 1)²] = 5√2

NS = √[(- 4 - 3 )² + (- 3 + 4)²] = 5√2

NA = AT = TS = NS = 5√2

$m_{NA}$ = (- 3 - 2) / (- 4 - 1) = 1 ........ <em>(1)</em>

$m_{TS}$ = (- 4 - 1) / (3 - 8 ) = 1 ......... <em>(2)</em>

From (1) and (2) ⇒ NA║TS

$m_{AT}$ = ( 1 - 2) / ( 8 - 1) = - 1 / 7 .......... <em>(3)</em>

$m_{NS}$ = ( - 4 + 3) / ( 3 + 4) = - 1 / 7 .... <em>(4)</em>

From (3) and (4) ⇒ AT║NS

Thus, NATS is rhombus.

4 0

3 years ago