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andriy [413]
3 years ago
14

What is the factored form of the expression?Factor completely.56k^3-84k^2+70k-105

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0
The best way to approach this problem is to start off by doing factor by grouping.

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and dat is onithhh purrrrr.. only of thee most respectfulyy sheesithhh

Step-by-step explanation:

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3 years ago
Can someone help me on problems 9, 10 and 11 please!!!
mojhsa [17]
9. i dissagree because 0.70 and 0.7 is the same thing
10. is 1.45
11. is 0.37
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3 years ago
A company manufactures and sells mini-recorders. A survey of office supply stores indicated that at a price of $82 each, the dem
Nutka1998 [239]
The first one. Substitute both $82 and $42 to get the 4 and 9 hundreds.

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3 years ago
A pet store has 6 cats 6,5,9,11,11,10 find the mean weight of these cats
aliina [53]

Answer:

8.7

Step-by-step explanation:

To find the mean first you have to add up all the weight of the cats which is:6+5+9+11+11+10= 52

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4 0
3 years ago
Can someone please please help me
velikii [3]

Answer:

  order: 2, 3, 1

Step-by-step explanation:

Reasonableness checks and your knowledge of integers and fractions will help you solve this. The offered questions are intended to help you think this through.

<h3>a.</h3>

For an output of -31, the machine (x -2)² cannot possibly be last. Its output can only be positive.

  machine 2, (x-2)², cannot be last

Also, machine 3 cannot be last. For the output to be -31, the input to machine 3 must be -1/31. Neither of the other machines can produce a fraction with the inputs they might receive.

<h3>b.</h3>

For an input of x=0, the machine 1/x cannot possibly be first. 1/0 is undefined.

The other two machines will give the following outputs for an input of 0:

  machine 1: 4(0) -32 = -32

  machine 2: (0 -2)² = 4

It is unlikely that machine 1 will be first, because the other two machines cannot do anything useful with -32 as an input.

  machine 3, 1/x, cannot be first

<h3>c.</h3>

The reasoning of part (a) tells you the last machine must be machine 1. The reasoning of part (b) tells you the first machine cannot be 3, so must be 2. The order of the machines must be ...

  • machine 2: (0 -2)² = 4 . . . . . . . using an input of 0
  • machine 3: 1/4 = 1/4
  • machine 1: 4(1/4) -32 = -31 . . . . desired output
7 0
1 year ago
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