1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
exis [7]
3 years ago
15

Is bse~ tes? if so, identify the similarity the similarity postulate or theorem that applies

Mathematics
2 answers:
hammer [34]3 years ago
8 0
The triangles are congruent by the SAS congruence theorem. By extension, we can also say they are similar using a closely related theorem. Any time there are congruent triangles, they are automatically similar.

This is why the answer is choice C) Similar - SAS

Note how
SB = ET ... which forms the first "S" in "SAS"
angle ESB = angle SET ... which forms the "A" in "SAS"
SE = SE ... which forms the second "S" in "SAS"
this is why SAS works
Basile [38]3 years ago
7 0

Answer:

SAS Similar

Step-by-step explanation:

pls dont troll. the answer is correct

You might be interested in
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
40 POINTS!!!!!!!! The length of a rectangle is 7 millimeters longer than its width. The perimeter is more than 62 millimeters.
Arte-miy333 [17]

a) L = W + 7  

b) 2 ( L + W ) > 62  

c) 2 ( W + 7 + W ) > 62  

2w+14+2w>62  

4w+14>62  

4w > 48  

w > 12

8 0
3 years ago
4 diff salds 7 kinds of pizza and 6 desserts how many options
babymother [125]
I would say 168 is the answer.
8 0
3 years ago
←
maw [93]

The equation that is represented by the graph below is y = e^x - 4.

<h3>How to illustrate the graph?</h3>

From the graph, it can be seen that the only exponential function n to hat intercept the function at equal to 3 is y = e^x - 4.

Let's equate y to 0.

y = e^x - 4.

e^x - 4 = 0

e^x = 4

In(e^x) = In(4)

x = 1.386

The x intercept is located at (1.386, 0).

In conclusion, the correct option is D.

Learn more about graph on:

brainly.com/question/12886416

#SPJ1

3 0
2 years ago
Cancel subscription
anzhelika [568]

Answer:

What do you want answered?

5 0
2 years ago
Read 2 more answers
Other questions:
  • A fair coin is flipped 3 times. It lands facing heads up 2 out of 3 times.
    5·1 answer
  • An experiment involves selecting a random sample of 256 middle managers at random for study. one item of interest is their mean
    5·1 answer
  • Convert decimal to percent 091:​
    12·2 answers
  • Find the missing length of x
    15·1 answer
  • Perform the indicated operation. 6/8 - 3/8
    14·1 answer
  • Label the vertices and state the Pythagorean Theorem for the following right triangle. Find x.
    9·1 answer
  • What would be the new ordered pair for point Q' given the following rule for the transformation?
    6·1 answer
  • Y=x^2-4x+5 to factored form
    9·1 answer
  • Which point is the reflection of (2,-5) on the
    14·1 answer
  • Someone pls help me on this! ASAP pls I’ll mark you as a brainliest.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!