What is the weight (in grams) of a liquid that exactly fills a 182.8 milliliter container if the density of the liquid is 0.135?
2 answers:
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Answer:
The last graph best represents the story
Step-by-step explanation:
Mary left for school from rest. So the initial speed is zero.
So we start from the origin and draw a straight line with a positive slope to running, that is as time increases , distance covered also increases.
When she is resting, her speed is zero so we draw a horizontal line to indicate this second phase of her journey.
After resting she still continued her journey to school.
This part also has a positive slope.
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Answer:
- 17.8 km
- 80.4 m
Step-by-step explanation:
The first attachment shows the sort of geometry involved. The line of sight from the top of the lighthouse makes a tangent with the earth's surface at the horizon (neglecting optical effects due to the atmosphere).
The hypotenuse of the relevant triangle is (r+h), and the angle is adjacent to the radius, r. Then the cosine relation applies:
Cos = Adjacent/Hypotenuse
cos(α) = r/(r+h)
We note that the radius is in km, and the length h is given in meters, so we need to do a conversion to put the numbers in this formula. We don't care so much about the angle itself, but we need its value to find the length of the arc along the earth's surface. That is ...
s = r·α
so, the distance of interest is found from ...
cos(α) = 6367/(6367 +0.025)
r·α = 6367·arccos(6367/6367.025) ≈ 17.84 . . . km
The horizon is about 17.8 km from the observer.
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The second problem requires we find the height value that makes the distance 32 km.
32 = r·α = 6367·arccos(6367/(6367 +h))
Dividing by the earth's radius and taking the cosine, we have ...
cos(32/6367) = 6367/(6367 +h)
h = 6367 -6367/cos(32/6367) ≈ 6367.0804 -6367 = 0.0804 . . . km
The cliffs must be about 80.4 meters high for it to be possible to see that distance.
