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Likurg_2 [28]
3 years ago
13

Prove that the median to the hypotenuse of a right triangle is half the hypotenuse,

Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer:

D. 2

Step-by-step explanation:

M(0,2b)

N(2a,0)

Then the midpoint P coordinates are

P\left(\dfrac{2a+0}{2},\dfrac{0+2b}{2}\right)\Rightarrow P(a,b)

Use distance formula to find OP and MN:

OP=\sqrt{(a-0)^2+(b-0)^2}=\sqrt{a^2+b^2}\\ \\MN=\sqrt{(2a-0)^2+(2b-0)^2}=\sqrt{4a^2+4b^2}=2\sqrt{a^2+b^2}

So,

MN=2OP

or

OP=1/2 MN

Click to let others know, how helpful is it

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Yuliya22 [10]
Area is calculated by multiplying length by width.  Since we are given the width, we can test each length and see if the product matches the rectangle's area.

(2m - 3)(4m - 4)  =  8m² - 20m + 12  ≠  8m² + 4m - 12

(8m - 3)(4m - 4)  =  32m² - 44m + 12  ≠  8m² + 4m - 12

(2m + 3)(4m - 4)  =  8m² + 4m - 12

(8m + 3)(4m - 4) =  32m² + 20m - 12  ≠  8m² + 4m - 12

The length of the rectangle must be 2m + 3.  Another method of solving this would be to divide the area by the width, or 8m² + 4m - 12  ÷  4m - 4.
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3 years ago
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Answer:

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