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3 years ago

Determine the sum of the following series: 2+6+18+54+...+39366

Mathematics

2 answers:

Fantom [35]3 years ago

8 0

The answer is 39446 i hope this helps

Anuta_ua [19.1K]3 years ago

7 0

Answer:

<em>59,048 </em>is the answer on K12 quiz

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Ashley has finished 7/25 of her homework what percentage of the homework does Ashley still need to finish

ludmilkaskok [199]

Answer:

72 percent

Step-by-step explanation:

7/25, x 4 to get a fraction of 100

28/100

100 - 28 = 72

72 percent

3 0

2 years ago

Read 2 more answers

Which expressionism equivalent to -60 / 5 select all that apply 60 divided by negitive 5 60 times 1/5 60 times negitive 1/5 Negi

GaryK [48]

Answer:

Equivalent expressions

A) $\frac{60}{-5}$

C) $60\times (-\frac{1}{5})$

Step-by-step explanation:

Given expression :

$\frac{-60}{5}$

Choices given :

A) $\frac{60}{-5}$

B) $60\times \frac{1}{5}$

C) $60\times (-\frac{1}{5})$

D) $-60\times (-\frac{1}{5})$

To find the equivalent expression.

We will first evaluate the given expression.

$\frac{-60}{5}$

⇒ $-12$ [Quotient of a negative dividend and a positive divisor is always negative]

Evaluating each choice to select the equivalents.

A) $\frac{60}{-5}$

⇒ $-12$ [Quotient of a positive dividend and a negative divisor is always negative]

B) $60\times \frac{1}{5}$

⇒ $\frac{60}{5}$

⇒ $12$

C) $60\times (-\frac{1}{5})$

⇒ $-\frac{60}{5}$ [Product of a positive and a negative is always a negative]

⇒ $-12$

D) $-60\times (-\frac{1}{5})$

⇒ $\frac{60}{5}$ [Product of two negatives is always a positive]

⇒ $12$

∴ We see that the choices A and C are equivalent.

7 0

3 years ago

Todd plans to swim 900 yards in a pool. So far Todd has swam 720 yards. What percentage of the total has Todd completed?

ella [17]

Answer:im pretty sure its 64.8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

A student did a survey on how people feel when they are hungry. The results were that more people felt a stabbing pain than thei

Kamila [148]

it’s 19 :)

filler

7 0

3 years ago