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Lelu [443]
3 years ago
11

How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this

temperature is 31.0 kJ/molkJ/mol.
Chemistry
1 answer:
KiRa [710]3 years ago
4 0

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = \frac{mass}{molar mass}

Number of moles of acetone = \frac{31.5}{58.08}

Number of moles  of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

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1) (Hvap)(moles of water)=236.9783574kJ
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Which landforms are created where cirques meet?
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The smallest unit of an element that maintains properties of that element is called a(n)
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how many moles of potassium dichromate (k2cr2o7) are required to prepare a 250-ml solution of with a concentration of 2.16 m?
Eva8 [605]

The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

given that :

molarity = 2.16 M

volume = 250 mL = 0.25 L

the molarity is given as :

molarity = number of moles / volumes in L

from this we can calculate the number of moles, we get :

number of moles of K₂Cr₂O₇ = molarity × volume

number of moles of K₂Cr₂O₇ = 2.16 × 0.25

number of moles of K₂Cr₂O₇ = 0.54 mol

Thus, The moles of potassium dichromate , K₂Cr₂O₇ are required to prepare a 250 mL solution of with a concentration of 2.16 M  is 0.54 mol.

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