2 years ago

What volume of 0.30 mol/L H2SO4(aq) is required to neutralize 50.0 mL of 0.60 mol/L NaOH (aq) ?

1 answer:

3 0

Explanation:

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d1i1m1o1n [39]

One is rows the other is columns

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2 years ago

podryga [215]

because it has ns1 electron configuration like the alkali metals

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2 years ago

swat32

The answer is D. Okay l hope this helps

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2 years ago

ivanzaharov [21]

Answer : The change in boiling point is, $0.94^oC$

Explanation :

Formula used :

$\Delta T_b=i\times K_f\times m$

where,

$\Delta T_b$ = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

$K_f$ = boiling point constant for water = $0.51^oC/m$

m = molality = 0.615 m

Now put all the given values in this formula, we get

$\Delta T_b=3\times (0.51^oC/m)\times 0.615m$

$\Delta T_b=0.94^oC$

Therefore, the change in boiling point is, $0.94^oC$

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3 years ago

zheka24 [161]

Because of how they grow

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2 years ago