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Anuta_ua [19.1K]
3 years ago
12

How did the elements begin to stratify?

Chemistry
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

The process of elemental stratification relies on the diffusion velocity, which causes the migration of the different chemical elements within stars.

Explanation:

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An atom has a mass number of 22 and an atomic number of 12. How many neutrons<br> does it have?
tia_tia [17]

Answer:

this isn't correct answer but the equation is correct by using this methid you can got your answer .

Explanation:

Given - Mass number of atom = 23

                                Atomic number of atom = 11

As, no. of electrons in an atom is equal to an atomic number of the element.

So, number of electrons = 11

Secondly , number of protons are equal to number of electrons.

so, number of protons = 11

And number of neutrons = mass number - atomic number = 23−11 = 12

so, number of neutrons = 12

So , the atom contains 11 protons, 11 electrons, 12 neutrons.

4 0
3 years ago
Which of the following elements has six valence electrons?<br> Be<br> B<br> C<br> N<br> O
Yakvenalex [24]
Oxygen (O) ,Neon (Ne),Argon (Ar)
7 0
3 years ago
Reactions tend to run to completion if a product
alisha [4.7K]

Answer: im pretty sure its B.

Explanation: sorry if im wrong. can i plz have brainliest??

7 0
3 years ago
What is the charge of phosphate in AlPO4?
Dennis_Churaev [7]

The charge of phosphate : 3-

<h3>Further explanation</h3>

Oxidation is an increase in oxidation number, while reduction is a reduction in oxidation number.

The formula for determining Oxidation Numbers in general:

1. Single element atomic oxidation number = 0.

Group IA (Li, Na, K, Rb, Cs, and Fr): +1

Group IIA (Be, Mg, Ca, Sr and Ba): +2

Group IIIA(Al, B) : +3

H in compound = +1, except metal hydride compounds (Hydrogen which binds to groups IA or IIA) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in an uncharged compound = 0,

Total oxidation number in ion = ion charge, Example NO₃⁻ = -1

Compound AlPO₄ :

The oxidation number in an uncharged compound = 0

Since the charge of Al as group 3A (or group 13) is +3, while the AlPO₄ compound is a polyatomic compound (consisting of polyatomic ions PO₄ and Al), the PO₄ charge:

charge Al + charge PO₄ = 0

+ 3 + charge PO₄ = 0

<em>charge PO₄ = -3</em>

6 0
2 years ago
Please help me with this, thank you so much
Basile [38]
I can’t answer the exact thing, but I know how to do it. One of the nitrogen bases always pairs with a different one, so once you know what pairs with what you just write it down. If you need more help just ask :) tip: one base will only join with a different one. One won’t join to multiple (from what I know as of now)
7 0
3 years ago
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