Triangle RTS is congruent to RQS by AAS postulate of congruent
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles
and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
∵ SR bisects angle TSQ ⇒ given
∴ ∠TSR ≅ ∠QSR
∴ m∠TSR ≅ m∠QSR
∵ ∠T ≅ ∠Q ⇒ given
∴ m∠T ≅ m∠Q
In two triangles RTS and RQS
∵ m∠T ≅ m∠Q
∵ m∠TSR ≅ m∠QSR
∵ RS is a common side in the two triangle
- By using the 4th case above
∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate
Triangle RTS is congruent to RQS by AAS postulate of congruent
Learn more:
You can learn more about the congruent in brainly.com/question/3202836
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If you're only counting the smallest triangles, then 8.
If you're counting all possible triangles including triangles made of other triangles, then 16. Each diagonal gives 2, the combined diagonals give 4, and the unit triangles give 8 for a total of 2 + 2 + 4 + 8 = 16.
3,800
because the rectangle area is 40x70 plus the triangle area is 40x50 divided by 2
Answer:
(7, 1/2)
Step-by-step explanation:
Multiply second equation by 2 and subtract.
3x - 4y = 19
- (4x - 4y = 26)
You get -x = -7
x = 7
Substitute x into any equation.
3(7) - 4y = 19
21 - 4y = 19
-4y = -2
y = 1/2
A!
hope this helps you out
