The coordinates of vertex B' is 
.
<h3>
How to calculate the coordinate of point by reflection</h3>
A point if reflected across the line 
by means of the following formula:
![P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)]](https://tex.z-dn.net/?f=P%27%28x%2Cy%29%20%3D%20P%28x%2Cy%29%2B2%5Ccdot%20%5B%28x_%7BP%7D%2C%20-2%29-P%28x%2Cy%29%5D)
(1)
Where:
- Original point
- x-Coordinate of point P
- Resulting point
If we know that 
and 
, then the coordinates of the vertex is:
![P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]](https://tex.z-dn.net/?f=P%27%28x%2Cy%29%20%3D%20%28-2%2C%204%29%20%2B%202%5Ccdot%20%5B%28-2%2C-2%29-%28-2%2C4%29%5D)
The coordinates of vertex B' is . 
To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272
Its 20 the sides are equal
Answer:
-3x-8=16
-3x = 16+8
-3x = 24
x = 24/-3
x = -8
= -2(x-7)
= -2(-8-7)
= 30
Hope this helps you. Do mark me as brainliest.
Wouldn't the formula be a×b/2?
As per Descartes Theorem, a polynomial of degree n (n is the highest exponent of a polynomial) has n roots (or number of zeros) be it positive, negative, real or complex.
in f(x) = x⁶ + x⁵ + x⁴ + 4x³ − 12x² + 12, the highest degree is 6, then it has
a total of 6 zeros, positive, negative, real or complex.
