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polet [3.4K]
3 years ago
5

I need to get this done as quick as possible. please help

Mathematics
1 answer:
ad-work [718]3 years ago
7 0
$5
——. = $2.50 per box
2 boxes
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The standard deviation of a normal random variable x is $20. given that p(x ≤ $10) = 0.1841. from this we can determine that the
attashe74 [19]
Let \mu be the mean of X. Then

\mathbb P(X\le10)=0.1841\iff\mathbb P\left(\underbrace{\dfrac{X-\mu}{20}}_Z\le\dfrac{10-\mu}{20}\right)=0.1841

For a random variable Z following the standard normal distribution, we have

\mathbb P(Z\le z)=0.1841\implies z\approx-0.8999

Transform the random variable to get this critical value in terms of \mu:

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strojnjashka [21]

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3 years ago
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Step-by-step explanation:

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