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ruslelena [56]
4 years ago
6

A kite is a quadrilateral with two pairs of adjacent, congruent sides. The vertex angles are those angles in between the pairs o

f congruent sides. Prove the diagonal connecting

Mathematics
1 answer:
umka21 [38]4 years ago
4 0

Let the kite is the quadrilateral A B C D with the two pairs of adjacent congruent sides. (Please find the attached diagram also) 

Now, its given in question, see from figure,

AB is congruent to AD 

BC is congruent to DC 

So, let us join the points A & C to form AC ; and points B and D to form BD. 

So, AC is common side  to triangles ABC and ADC. 

So, Because AB ≈AD

BC ≈ DC

And, AC is common, therefore, 

triangle ABC is congruent to triangle ADC 

⇒∠ ABC ≈ ∠ADC

The above are the angle.

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Gizmo can eat 2 bowls of kibbles in 3 minutes. Leo can eat one bowl of kibbles in 6 minutes. Together, how many bowls of kibbles
Westkost [7]
Gizmo eats two bowls in 3 minutes, which means in a minute he would eat a fraction of 2/3 of the bowl.
On the other hand, leo eats one bowl in 6 minutes hence in a minute he eats a fraction of 1/6 of a bowl. 
When both combine, then in one minute they can eat a fraction of 2/3+1/6= 5/6.
Therefore, in ten minutes they will take 10× 5/6 = 8.333 equivalent to 8 bowls and a third of a bowl
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3 years ago
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Masteriza [31]

Answer: ∞

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3 years ago
Mark as brainliest
almond37 [142]

Answer:

C) Casey is incorrect because more than one student can have the same GPA.

Step-by-step explanation:

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3 years ago
A pitcher struck out 11 out of 40 batters. Write an equivalent decimal.
Komok [63]

Answer:

0.275

Step-by-step explanation:

We want to write 11 out of 40 batters as a decimal.

We can write 11 out of 40 as a fraction to get:

\frac{11}{40}

Note that:

\frac{11}{40}  =  \frac{1}{4}  \times  \frac{11}{10}

This implies that:

\frac{11}{40}  = 0.25  \times 1.1

This gives us

\frac{11}{40 }  = 0.275

5 0
3 years ago
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
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