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Goshia [24]
3 years ago
12

WILL MARK BRAINLIEST A stamp collector bought 7 rare stamps for her collection. Each stamp cost $1,953. How much did the collect

or spend on the rare stamps?*
Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

$13,671

Step-by-step explanation:

Each stamp cost $1,953, and the collector bought 7 of them.

1953 * 7 = 13671

The collector spent $13,671 on the stamps.

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Please help! Problem is attached
Darya [45]

Answer:

  (a)  -3

Step-by-step explanation:

The value of f(x) approaches 3cos(π) = -3 as x approaches π from either direction. The limit is -3.

__

<em>Additional comment</em>

The fact that the function is defined to have a different value at x=π simply means there is a jump discontinuity there. The function is <em>not continuous</em>, because the limit and the function value differ. That doesn't detract from the fact that there is a limit, and it is -3.

6 0
3 years ago
Simplify the following expression: (67 − 18) ÷ 7 × 3
Alexxx [7]

Answer:

21, You have to subtract 67 by 18, then multiply 7 by 3 then divide together both of their answers.

5 0
3 years ago
Read 2 more answers
What is the square root of 25/64
DerKrebs [107]
The square root of 25/64=5/8
4 0
3 years ago
Read 2 more answers
Question 3
Scilla [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the vertices of the triangles is missing.

However, the following formula can be used to calculate distance;

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

Take for instance:

A = (1,8)

A' = (7,8)

The distance between both is:

d = \sqrt{(1- 7)^2 + (8- 8)^2}

d = \sqrt{(-6)^2 + 0^2}

d = \sqrt{36 + 0}

d = \sqrt{36}

Take square root

d = 6

<em>Apply the above steps to the complete question</em>

6 0
3 years ago
GIVING BRAINILEST-
Nutka1998 [239]

Answer:

To construct a dilation, we need the center of dilation, which is the point from which we make the image smaller or larger. We also need a scale factor, which is the number that determines how large or small we are making the new image. If the scale factor is greater than 1, we have an enlargement, because the new image will be larger than the original image. If the scale factor is less than 1, we have a reduction because the new image will be smaller than the original image.

Enlargement

Step-1

Let's dilate triangle PQR by a scale factor of 2 with a center of dilation at point C.

Step-2

First, we will use a straightedge to connect the center of dilation C to each vertex. We are going to extend those lines across the whole page.

Step-3

Next, we'll place the point of the compass on the center of dilation C and the pencil on vertex Q and measure that distance.

Step-4

Now, without changing the size of the compass, we will move the point of the compass to vertex Q, and make a mark on the line that is extended through Q.

Step-5

Notice that since we measured the distance from C to Q and then used that same distance to mark the line, we have now created a new point that is twice the distance from C that Q was.

We now repeat the process for each of the other vertices of the triangle.

Step-6

These marks represent the vertices of our dilated image. We often use the same letters with an apostrophe to show that it is the corresponding vertex.

Step-7

Finally, we use the straightedge to connect all of the new vertices.

Now,See how triangle P

′

Q

′

R

′

is twice the size of the original triangle.

Reduction

Step-1

Given triangle PQR, now let's dilate the image with a center of dilation at C and with a scale factor of

2

1

Step-2

Using the straightedge, we will connect all of the vertices to the center of dilation C. In this case, since our scale factor is less than 1, we are reducing the size of the triangle.

Step-3

The green lines are the new lines that we have drawn.

Since we have to reduce the size of the triangle by half, we want to cut the distance in half from each vertex to the center of dilation. In order to do this, we will set our compass to a distance that is more than halfway between vertex P and point C but less than the total distance.

Step-4

Keeping the compass at that same distance, start with the point of the compass on vertex P, then draw a curve that intersects the line between P and C. Next, keeping the compass at the same distance, place the point of the compass on C and draw a curve that intersects the line between P and C and intersects the previously drawn curve.

Step-5

Now, we will take the straightedge and connect the points where the curves overlap.

4 0
3 years ago
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