Answer: 2x + 5y = -5
Step-by-step explanation:
Two lines are said to be parallel if they have the same slope.
The equation of the line given :
2x + 5y = 10
To find the slope , we will write it in the form y = mx + c , where m is the slope and c is the y - intercept.
2x + 5y = 10
5y = -2x + 10
y = -2/5x + 10/5
y = -2/5x + 2
This means that the slope is -2/5 ,the line that is parallel to this line will also have a slope of -2/5.
using the formula:
= m (
) to find the equation of the line , we have
y - 1 = -2/5(x -{-5})
y - 1 = -2/5 ( x + 5 )
5y - 5 = -2 ( x + 5 )
5y - 5 = -2x - 10
5y + 2x = -10 + 5
therefore :
2x + 5y = -5 is the equation of the line that is parallel to 2x + 5y = 10
Answer:
Step-by-step explanation:
So 18 oranges are 12 percent of her total oranges. You can use Ratio to solve this.
O : P
18 : 12 P = Percentage O = Orange
1.5 : 1
150 : 100
All I did was make the percentage one by dividing both numbers by 12. This makes it 1.5 oranges per percent. Times 1.5 with 100 to make it 100 percent.
Product is multiplication.
Let the number = x
3 *( X+7) = -36
Use distributive property:
3x +21 = -36
Subtract 21 from each side:
3x = -57
Divide both sides by 3:
x = -57 /3
x = -19
Check: 3 * (-19 +7) = 3 * -12 = -36
The number is -19
Answer:
Option b. should not be rejected
Step-by-step explanation:
We are given that the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.
We have to test whether the variance of the population is significantly more than 0.003, i.e.;
Null Hypothesis,
:
=
Alternate Hypothesis,
:
The test statistics used here for testing variance is;
T.S. =
~
where, s = sample standard deviation = 0.06
n = sample size = 26 cans
So, Test statistics =
~ 
= 30
So, at 5% level of significance chi square table gives critical value of 37.65 at 25 degree of freedom. Since our test statistics is less than the critical so we have insufficient evidence to reject null hypothesis.
Therefore, we conclude that null hypothesis should not be rejected and variance of population is 0.003.