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vlabodo [156]
3 years ago
5

Avenues A,B, and C are parallel to each other, and are perpendicular to the 7th street. What is the length (x) of the block on b

roadway between Avenues B and C to the nearest tenth? someone please help

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer:

The length (x) of the block on broadway between Avenues B and C is 101.9 m.

Step-by-step explanation:

Given Avenues A,B, and C are parallel to each other, and are perpendicular to the 7th street. we have to find the length (x) of the block on broadway between Avenues B and C to the nearest tenth.

By theorem, if two or more parallel lines are cut by two transversals lines, then they divide the transversals proportionally i.e

If A || B || C, then

\frac{\text{distance of broadway from A and B}}{\text{distance of broadway from B and C}}=\frac{\text{distance of 7th street from A and B}}{\text{distance of 7th street from B and C}}

⇒ \frac{214-x}{x}=\frac{110}{100}

⇒ 2140-10x=11x

⇒ 21x=2140

⇒ x=\frac{2140}{21}=101.9

Hence, the length (x) of the block on broadway between Avenues B and C is 101.9 m.

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Please help! 56 points. Greatly appreciated!
VashaNatasha [74]

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Step-by-step explanation:

41 square miles If you draw the outline of the city, you'll realize that if you draw a line from point B to point D, that you can subdivide the city into a triangle and a trapezoid. After performing the division, you can then calculate the area of both polygons and the add their areas together. So first, let's deal with the trapezoid ABDE. The area of a trapezoid is the average of the length of the parallel sides multiplied by the height. The parallel sides are AB and DE. So: ((18-10)+(14-10))*(9-4.5)/2 =(9 + 4)*(4.5)/2 = 12*4.5/2 = 27 Now for the area of triangle BCD. The area of a triangle is 0.5*b*h where b is the base and h the height. I'll use BC as the base and the distance from BC to D as the height. So: (9-2)*(18-14)/2 = 7*4/2 = 14 And now to add the areas. 27 + 14 = 41 So the area of the city is 41 square miles. Note: The subdivision used is not the only possible subdivision, just one of the easier ones. I could have divided the city area into 3 triangles ABE, BDE, and BCD and solved it that way instead. It was just a happy coincidence that AB and DE were parallel and as such I was able to use trapezoid ABDE instead of the two triangles ABE and BDE.

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