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vlabodo [156]
3 years ago
5

Avenues A,B, and C are parallel to each other, and are perpendicular to the 7th street. What is the length (x) of the block on b

roadway between Avenues B and C to the nearest tenth? someone please help

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer:

The length (x) of the block on broadway between Avenues B and C is 101.9 m.

Step-by-step explanation:

Given Avenues A,B, and C are parallel to each other, and are perpendicular to the 7th street. we have to find the length (x) of the block on broadway between Avenues B and C to the nearest tenth.

By theorem, if two or more parallel lines are cut by two transversals lines, then they divide the transversals proportionally i.e

If A || B || C, then

\frac{\text{distance of broadway from A and B}}{\text{distance of broadway from B and C}}=\frac{\text{distance of 7th street from A and B}}{\text{distance of 7th street from B and C}}

⇒ \frac{214-x}{x}=\frac{110}{100}

⇒ 2140-10x=11x

⇒ 21x=2140

⇒ x=\frac{2140}{21}=101.9

Hence, the length (x) of the block on broadway between Avenues B and C is 101.9 m.

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\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
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A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

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2 years ago
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