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Leokris [45]
3 years ago
14

Youth tickets(y) cost $2 for a ride, while adult tickets(x) cost $3. The amount of money earned is $54. If all the seats were fi

lled(24 seats), how many of each ticket was sold?
Mathematics
1 answer:
Paha777 [63]3 years ago
7 0
There are no constants here. But we have x and y here.
We will create an equation which is:
2y+3x=54.
But we will also create a second equation which states the number of seats.
x+y=24.

Now we do the two-equation solving method.
2y+3x=54
-2(x+y=24)

2y+3x=54
-2x-2y=-48

x=6

To solve for y, plug in x into one of the original equations. Which one doesn't matter.

y+6=24
y=18

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The perimeter of a rectangle is 54 feet. The area of the rectangle is 176 square feet. Find the dimensions of the rectangle.
Murrr4er [49]

11 by 16

Explanation:

Set up two equations

2

x

+

2

y

=

54

x

×

y

=

176

Solving the first equation for x

2

x

+

2

y

−

2

y

=

54

−

2

y

this gives

2

x

=

54

−

2

y

Divide both sides by 2

(

2

x

2

)

=

54

−

2

y

2

This gives.

x

=

27

−

y

putting this value into the second equation gives.

(

27

−

y

)

×

y

=

176

multiplying across the parenthesis gives

27

y

−

y

2

=

176

subtracting 176 from both sides gives

is

27

y

−

y

2

−

176

=

0

multiplying by negative one gives

−

27

y

+

y

2

+

176

=

0

factoring this into y gives

(

y

−

11

)

×

(

y

−

16

)

=

0

Solving for both y's gives

y

=

11

,

y

=

16

6 0
2 years ago
a new statue with a circular base is being unveiled in a downtown park. the statue base has a radius of 8 feet. round your answe
fiasKO [112]
I believe you are asking for the area of the statue base.

r^2x3.14 = area of a circle

8 x 8 = 64

64 x 3.14 = 200.96
200.96 rounded = 201

The area of the statue base is 201 square feet.
5 0
3 years ago
What is 0.000000028 in scientific notation
Papessa [141]
2.8 X 10^-8 (........characters space so that I can post this..)
8 0
3 years ago
Read 2 more answers
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
Find the point(s) in which f(x)=e^5-2x and y=6 intercept
Nana76 [90]

Answer:

(1.6, 6)

Step-by-step explanation:

ln({e}^{5 - 2x}  = 6)

5 - 2x =  ln(6)

2x = 5 -  ln(6)

x =  \frac{5 -  ln(6) }{2}

y = 6

7 0
3 years ago
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