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jarptica [38.1K]
3 years ago
14

Kelly sells ice cream bars at the beach. In addition to a fixed salary, she earns a commission for each ice cream bar she sells.

The table shows Kelly's total earnings, y, in dollars, from selling x bars of ice cream:
Ice Cream Sales and Earnings
Number of Bars Sold (x)
Total Earnings (dollars) (y)

(x) (y)
0 50
1 52
2 54
3 56


Which equation best shows the relationship between x and y? (5 points)
 

a. y = 2x + 50

b. y = x + 52

c. y = 2x + 52

d. y = x + 50
Mathematics
2 answers:
sergey [27]3 years ago
8 0
If my math is right it would be y = 2x + 50<span>
</span>
S_A_V [24]3 years ago
6 0

Answer: y=2x+50



Step-by-step explanation:

Given: The salary of Kelly is fixed but she earns a commission for each ice cream she sells.

Thus, Her earning will be a linear function dependent upon the number of bars she sold.

Since y represents the total earning of Kelly on selling x bars of ice- cream.

We can see at x=0, y=50

Thus her fixed salary=$50

Then, y=mx+50, where m is the commission she gets for each ice cream.

Also at x=1, y=52.....> put thus in above equation

Then, 52=m(1)+50\\\Rightarrow\ m=52-50\\\Rightarrow\ m=2

hence, the equation best shows the relationship between x and y is :-

y=2x+50


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Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

1)

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

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m= 5/2

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2)

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

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2 years ago
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astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

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