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USPshnik [31]
3 years ago
12

Which expression is equal to 3√54 − 4√24 ? −11√16 −√6 √6 11√6

Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
3√54-4√24=
(3√3.3.3.2)-(4√2.2.2.3)=
9√6-8√6=√6
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Because 3/6 is equal to 1/2.
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V - 4/5 equals 4 1/4 what does v equal ​
yulyashka [42]
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A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc
lina2011 [118]

Answer:

The ball will take 6.3 seconds to reach the maximum height and hit the ground.

Step-by-step explanation:

a). When a ball was thrown upwards with an initial velocity u then maximum height achieved h will be represented by the equation

v² = u² - 2gh

where v = final velocity at the maximum height h

and g = gravitational force

Now we plug in the values in the equation

At maximum height final velocity v = 0

0 = (28)² - 2×(9.8)h

19.6h = (28)²

h = \frac{(28)^{2}}{19.6}

  = \frac{784}{19.6}

  = 40 meter

B). If the ball misses the building and hits the ground then we have to find the time after which the ball hits the ground that will be

= Time to reach the maximum height + time to hit the ground from the maximum height

Time taken by the ball to reach the maximum height.

Equation to find the time will be v = u - gt

Now we plug in the values in the equation

0 = 28 - 9.8t

t = \frac{28}{9.8}

 = 2.86 seconds

Now time taken by the ball to hit the ground from its maximum height.

H = ut + \frac{1}{2}\times g\times (t)^{2}

(17 + 40) = 0 + \frac{1}{2}\times g\times (t)^{2}

57 = 4.9(t)²

t² = \frac{57}{4.9}

t² = 11.63

t = √(11.63)

 = 3.41 seconds

Now total time taken by the ball = 2.86 + 3.41

                                                      = 6.27 seconds

                                                      ≈ 6.3 seconds

Therefore, the ball will take 6.3 seconds to reach the maximum height and hit the ground.

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4 years ago
Question 4 Alan is y years old and has 8 sisters.
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Answer:

I think your answer is correct my friend

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Answer:

7^5=16,807 and 4^5=1,024

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