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Anettt [7]
3 years ago
15

John had 2⁄3 of his homework complete, Sarah had 5⁄10, Alex 7⁄8, and Michelle 1⁄2. Who completed the most of the homework assign

ment? A. Sarah B. Michelle C. Alex D. John
Mathematics
1 answer:
yuradex [85]3 years ago
4 0
Hey there!

So, when finding who completed more, we would want to find the lowest denominator, but also, we would have to compare it with the numerator.

John: He completed 2/3, which is basically almost done.

Sarah: She only completed (half) of her homework.

Alex: He only did 7/8

Michelle: He/she only did 1/2, which is only half.

So, from looking at these fractions above, Michelle and Sarah are out.

We would just have to determine, which is finished more, John or Alex.

John had 2/3 & Alex 7/8

So, by comparing them both, 7/8 would be greater because the smaller the denominator is, and the closer that the numerator is to the denominator, this would mean that the homework is almost finished.

Your correct answer is Alex, he has completed more.

Hope this helps you!
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The value of given expression when m = 3 is 27

<h3><u>Solution:</u></h3>

Given expression is 3m^2

We have to evaluate the given expression for m = 3

To find for m is equal to 3, substitute m = 3 in given expression

From given expression,

\rightarrow 3m^2

Plug in m = 3 in above expression

\rightarrow 3(3)^2 ------ eqn 1

We know that,

a^2 can be expanded as,

a^2=a \times a

Applying this in eqn 1, we get

\rightarrow 3(3)^2=3 \times (3 \times 3)

Simplify the above expression

\rightarrow 3(3)^2=3 \times (3 \times 3) = 3 \times 9 = 27

Therefore, for m = 3 we get,

\rightarrow 3(3)^2=27

Thus value of given expression when m = 3 is found

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3 years ago
Two rays that meet at the same point
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What is the measure of the hypotenuse?
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<h2><em>Answer:</em></h2><h3><em>1</em><em>3</em></h3>

<em>solution \\ hypotenuse = x \\ base = 12 \\ perpendicular = 5 \\ using \: pythagoras \: theorem \\  {h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {x}^{2}  =  {5}^{2}  +  {12}^{2}  \\ or \:  {x}^{2}  = 25  + 144 \\ or \:  {x}^{2}  = 169 \\ or \: x =  \sqrt{169}  \\ x = 13 \\</em>

<em>hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Answer:

The minimum value of the width is 15 ft and the maximum value of the width is 30 ft

Step-by-step explanation:

Let

x -----> the length of the deck

y ----> the width of the deck

we know that

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P=2(x+y)

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so

90=2(x+y)

45=(x+y)

x=45-y -----> equation A

The area is equal to

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Solve the quadratic equation by graphing

The possible width of the deck are the values of y in the interval

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see the attached figure

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7 0
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Answer:

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Step-by-step explanation:

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Regroup similar terms to get:

12x^2-19x^2-28x

Combine the similar terms to obtain:

-7x^2-28x

The correct option is C.

5 0
3 years ago
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