Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:
b) The probability that both are defective is given by:
c) The probability that both are acceptable is given by:
d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:
e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:
f) The probability that all three are defective is given by:
Answer:
positive
Step-by-step explanation:
if x is positive then for all values 5x^3 which is always>-2x will be positive and therefore answer always positive
if x is negative then 5x^3 will always be positive and -2(X) will cancel the two minuses -- and will add therefore positive
Answer:
C. ![\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The given matrices are;
![F=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=F%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
and
![C=\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{ccc}12(-2)+0(1)&0(-2)+-6(0)&\frac{3}{2}(-2)+7(0)\\12(0)+8(1)&0(0)+8(-6)&0(\frac{3}{2})+8(7)\\2(12)+1(1)&2(0)+1(-6)&2(\frac{3}{2})+1(7)\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%281%29%260%28-2%29%2B-6%280%29%26%5Cfrac%7B3%7D%7B2%7D%28-2%29%2B7%280%29%5C%5C12%280%29%2B8%281%29%260%280%29%2B8%28-6%29%260%28%5Cfrac%7B3%7D%7B2%7D%29%2B8%287%29%5C%5C2%2812%29%2B1%281%29%262%280%29%2B1%28-6%29%262%28%5Cfrac%7B3%7D%7B2%7D%29%2B1%287%29%5Cend%7Barray%7D%5Cright%5D)
This simplifies to;
![FC=\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
The correct answer is C
The answer is 46 yards with 1 ft.
You have to divide 139 with 3 and then it comes pout as 46 with some decimals, but just search up how much is 46 yards and then you see that only a ft is left over.
Can u pls give brainly?
Answer:
<u> The distance between opposite corners of the windowpane is 8.5 inches (rounding to the nearest tenth).</u>
Step-by-step explanation:
1. Let's use the Pythagorean Theorem to find the distance between opposite corners of the windowpane:
With the information given, we have a right triangle with the distance between opposite corners of the windowpane as the hypotenuse and its sides of 6 inches as the width and length of the windowpane and as sides of the right triangle.
Distance between opposite corners of the windowpane ² = Width of the windowpane ² + Length of the windowpane ²
Replacing with the real values:
Distance between opposite corners of the windowpane ² = 6² + 6²
Distance between opposite corners of the windowpane ² = 36 + 36
Distance between opposite corners of the windowpane ² = 72
√ Distance between opposite corners of the windowpane² = √72
<u> Distance between opposite corners of the windowpane = 8.5 inches (rounding to the nearest tenth)</u>
