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aliina [53]
3 years ago
9

Find the HCF of 150 and 180.

Mathematics
2 answers:
svp [43]3 years ago
6 0

Answer:

The HCF of 150 and 180 is 30

Hope this helps

Ratling [72]3 years ago
3 0

Answer:

30 is ans do you know hindi

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Solve this equation -9h - 6 + 12h + 40 = 22
schepotkina [342]

-9h - 6 + 12h + 40 = 22\\\\3h=-12\\\\h=-4

5 0
3 years ago
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The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that
salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0
4 years ago
Graph each function.<br> Which option is correct?
Gre4nikov [31]

Answer:

Answer is the second one

Step-by-step explanation:

Log

log(x - 2)

X-2 means it is shifted to the right by 2 units also there is no negative before log so it os not reflected

7 0
3 years ago
What is the solution to this equation ? x + 12 +3x =18 - 2x
olasank [31]

First, you combine like terms: x+3x=4x: 12+4x=18-2x

Second, you add the 2x to each side (inverse operation): 12+6x=18

Third, you subtract 12 from 18 to cancel out the 12 (inverse operation): 6x=6

Fourth, you divide each side by 6 to find the value of x

The answer is x=1

3 0
3 years ago
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In a class of 40 students, 8 are in the drama club and 12 are in the art club. If a student is selected at random, what is the p
babymother [125]

Answer:

total students = 40probability of selecting a student from art club= 12/40= 3/10

Step-by-step explanation: because am big math

4 0
2 years ago
Read 2 more answers
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