The <em><u>correct answer</u></em> is:
C) Draw QS so that S is the midpoint of PR, then prove ΔPQS is congruent to ΔRQS using SSS.
Explanation:
We cannot use ∠P or ∠R in the proof, since they are part of the theorem we are trying to prove.
We know that PQ and QR are congruent, as we are given that information. If we draw a segment from Q to PR, this segment will be part of both triangle PQS and RQS. This gives us 2 sides congruent.
If we draw QS so that S is the midpoint of PR, then by definition PS is congruent to SR. This gives us 3 sides of both triangles that are congruent, which means the side-side-side congruence theorem applies and the triangles are congruent.
Since the triangles are congruent, this means corresponding angles are congruent, and ∠P is congruent to ∠R.