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3 years ago

Which of the binomials below is a factor of this trinomial? x2 - x-12 A) x+6 B) x+4 C) x-4 D) x-6

Mathematics

1 answer:

andre [41]3 years ago

8 0

Start by setting up your two sets of parenthses.

X² breaks down into x and x.

What we are looking for is factors of the constant term

that add to the coefficient of the middle term.

The question is, what is the coefficient of the middle term

in this problem if there is nothing written in front of the x.

Well if there is nothing written there,

the coefficient is understood to be 1.

So what we are looking for are factors of -12 that add to -1.

<em><u>Factors of -12</u></em>

+12 · -1

-12 · +1

+6 · -2

-6 · +2

+4 · -3

-4 · + 3

We can see that -4 and +3 add to -1.

So they go in the second position of each binomial.

This gives us (x - 4)(x + 3) as our answer.

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Find the equivalent fraction for 10/20

dezoksy [38]

$\frac{10}{20} = \frac{ \frac{10}{10} }{ \frac{20}{10} } = \frac{1}{2}$

6 0

3 years ago

MATH help right now plzzz HURRY NOOW NOW NOW 2 ATTACHMENTS GIVING A BRAINLIEST ANSWER ALL

Nikolay [14]

First one is D
Second one is B.

3 0

3 years ago

Read 2 more answers

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

3 years ago

HELP^^ LOOK AT THE PICTURE. this is algebra in & out tables ?

s2008m [1.1K]

Answer:

a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81

Step-by-step explanation:

The first table is given as;

x 4⁻ˣ

-1 4

0 1

2 1/16

4 1/256

a= 1 , b = 1/16 , c = 1/256

The second table is given as;

x {2/3}^x

-1 3/2

0 1

2 4/9

4 16/81

d= 3/2 , e=4/9 , f= 16/81

5 0

3 years ago

Can someone please answer. There is one problem. There is a picture. Thank you!

jonny [76]

SA=4pir^2
78.54km^2=SA
78.54=4pir^2
divide both sides by 4
19.635=pir^2
aprox pi=3.14 so divide both sides by 3.14
6.25318=r^2
sqrt both sides
2.50063=r
round
radius=2.5km

this question is flawed in that it gives the wrong units

answer is the option with 2.5 in it
2nd one

5 0

3 years ago