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boyakko [2]
3 years ago
13

Question 3 (3 points) Solve 8 = 2x + 4. (3 points)

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0

X=2

-4 on both sides

4=2x

divide by 2 on both sides

X=2

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Using a formula estimate the body surface area of a person whose height is 150 cm and who weighs 80 kg.
ladessa [460]

Answer:

B. 1.83\text{ m}^2

Step-by-step explanation:

We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

\text{Body surface area}( m^2)=\sqrt{\frac{\text{Height (cm)}\times \text{Weight (kg)}}{3600}}

Substitute the values:

\text{Body surface area}( m^2)=\sqrt{\frac{150\text{ cm}\times 80\text{(kg)}}{3600}}

\text{Body surface area}( m^2)=\sqrt{\frac{12,000}{3600}}

\text{Body surface area}( m^2)=\sqrt{3.3333333}

\text{Body surface area}( m^2)=1.825741

\text{Body surface area}( m^2)=1.83

Therefore, the body surface area of the person would be 1.83 square meters.

7 0
3 years ago
What is the value of n in the equation; 3n - 8 = 32 - n?
Marrrta [24]
N=10
3n-8=32-n
+8 +8
3n=40-n
+n +n
4n=40
Divide
n=10
7 0
3 years ago
Compute the requested average.
AnnZ [28]
230.83 is your answer
5 0
3 years ago
Over 1,000 people try to climb Mt. Everest every year. Of those who try to climb Everest, 31 percent succeed. The probability th
Anit [1.1K]

Answer:

A- 0.125

B- Success of climbing mount Everest is independent of age.

Step-by-step explanation:

A.

Let x denote success in climbing Mount Everest

Let y denote the climber is at least 60 years old.

Therefore,

P(x) = 0.31

P(y) = 0.04

P( x ∩ y) = 0.005

Probability of success when the climber is at least 60 years old =

P( x ∩ y) ÷ P(y) = 0.005 ÷ 0.04 = 0.125.

B.

The success rate is independent of age as there are both success and failure rates across board on the scale of ages of climbers.

7 0
4 years ago
Carlos' monthly office budget is $250. He needs to buy ink cartridges, which cost $40 a piece. he will save at least $50 of his
levacccp [35]

Answer:

26

Step-by-step explanation:

yeah

5 0
3 years ago
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