Circles with centers (2,1) and (8,9) have radii 1 and 9, respectively. The equation of a common external tangent to the circles
1 answer:
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Answer:
4x - 3y -18 = 0 or y = 4x/3 - 6
Step-by-step explanation:
We will have to find the slope of the line first
The formula for slope:
The standard form of equation of a line is:
y = mx + b
We know m,
So the equation will be:
We have to find the value of b, for that we will put any one of the point in the equation
So, putting (6,2)
2 = 4/3 * 6 + b
2 = 8 +b
b = -6
Putting the value of m and b in the standard form of equation of line,
..
Step-by-step explanation:
1) i will asume x2 and z2 are squares here.
ok, here we only have restrictions to x and z, so y can take all the values in R.
is a circle of radius 6, you can see this if for example we set z = 0, then x goes from -6 to 6, the same if we set x = 0 then z goes from -6 to 6.
and the equation describes a circle.
So here, the region is the solid cylinder of radius 6, where the Y axis is also the axis of the cylinder.
2) you tipped the same inequality but different numbers in the right side, here i think you are saying that the inequalities describes the set of all points whose distance from the y-axis is equal or less tan 6.