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IrinaVladis [17]
3 years ago
14

Circles with centers (2,1) and (8,9) have radii 1 and 9, respectively. The equation of a common external tangent to the circles

can be written in the form y=mx+b with m < 0. What is b?
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0
B=30/7 and 80/7

hope this helps<3

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What are the factors of 3x2 + 13x + 4?
padilas [110]
S<span>tep-1 : Multiply the coefficient of the first term by the constant </span><span> <span> 3</span> • 4 = 12</span> 

<span>Step-2 : Find two factors of </span> 12 <span> whose sum equals the coefficient of the middle term, which is  </span><span> 13 </span><span>.
</span><span><span>

-12   +   -1   =   -13</span><span>     
-6   +   -2   =   -8</span><span>     
-4   +   -3   =   -7</span><span>     
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-2   +   -6   =   -8</span><span>     
-1   +   -12   = -13</span><span>     
1   +   12   =   13 </span></span>
5 0
3 years ago
Read 2 more answers
Which of the following relations is a function? A.{ (-2, 4), (-1, 3), (5, 2), (1, 4) } B.{ (1, 7), (1, 8), (2, 7), (3, 8) } C.{
siniylev [52]
From the pairs of x,y, if the set has two "x" of the same value, that is, "x" repeats, or an x-repeat, then is NOT a function

so, the group that doesn't have any x-repeats, is a function, now let's check

\bf A.\{ (-2, 4), (-1, 3), (5, 2), (1, 4) \}\\\\&#10;B.\{ (\boxed{1}, 7), (\boxed{1}, 8), (2, 7), (3, 8) \}\impliedby \textit{has one re}\textit{peat, no dice}\\\\&#10;C.\{ (2, 4), (\boxed{4}, 6), (\boxed{4}, 8), (6, 4) \}\impliedby \textit{also has one re}\textit{peat, no dice}\\\\&#10;D.\{ (\boxed{5}, 7), (6, 3), (8, 6), (\boxed{5}, 4) \}\impliedby \textit{same, has one re}\textit{peat, no dice}
3 0
3 years ago
PLZ HELP ME ASAP W THIS !!!
ratelena [41]

Answer:

(2x+3) x (x-7)

Step-by-step explanation:

3 0
3 years ago
Help pls this is 5th grade math
stich3 [128]

Answer:

1.35

2.54

3.32

4.64

5.121

6.70

8 0
3 years ago
the length of a rectangle is 7 inches more than its width, if the perimiter of the rectangle is 66 inches, find its dimensions.
Maurinko [17]
Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w

if the length is 7in more than the width, then
L=7+w

Now we will substitute 7+w in for L. Here is our new equation:

66=2(7+w) + 2w

Solve for w

66=14+2w+2w
66=14+4w
52=4w
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L=7+13, so L=20

I hooe this is explained well enough
3 0
4 years ago
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