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3 years ago

6

Find the sum of interior angles a polygon has with the given number of sides a.9 b.19

1 answer:

Gnom [1K]3 years ago

4 0

The equation for this is (n-2) x 180

Replace n with the number of sides:

a. 9: (9-2) x 180 = 7 x 180 = 1,260

b. 19: (19-2) x 180 = 17 x 180 = 3,060

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A quadrilateral has angles that measure 56°, 97°, and 136°. What is the measure of the fourth angle?

Aleksandr [31]

The quadrilateral adds up to 360 degrees.

the 3 angles given add up to 289 degrees.

subtract the 3 given from 360

360 - 289

71 degrees.

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3 years ago

Ms. Gallegos burns 236 calories riding her bike each hour.

Delicious77 [7]

Answer:

the answer is B.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

3 years ago

" 250 = x(34-x) solve x "

Andrews [41]

250=x(34-x) solve X "

the equation $x^{2} +250= 34x - x^{2} + x^{2} = 250x=34x 
$

X= 7.35

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3 years ago

Jack has 3 boxes of pencils with the same number of pencils in each box his mom gives him 4 more pencils now jack has 28 pencils

labwork [276]

Hope this answer is helpful and correct.

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3 years ago