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mojhsa [17]
4 years ago
14

Marley has read 112.5 pages of a book. By the end of today, she plans to have read at least a total of 360 pages. If she reads 4

5 pages per hour, what is the minimum amount of time she should devote to reading today?
Mathematics
1 answer:
Rufina [12.5K]4 years ago
7 0

Answer:

5 \frac{1}{2} hours

Step-by-step explanation:

We are told that, Marley has already read 112.5 pages of the book.

Marley also plans to read at least 360 pages in all.

Now, let x be at least the number of pages Marley is let to read to achieve her goal.

This implies that

x \geqslant 360 - 112.5

\implies  x \geqslant 247.5

This means that Marley would have been reading at least 247.5 pages

Moreover, we are told that Marley reads 45 pages every hour.

Hence to find the minimum amoutnt of timeof time (let say y) she should devote fkr reading, we divide the number of pages she has left to read by 45.

This implies

y \geqslant  \frac{247.5}{45}

\implies y\geqslant 5 \frac{1}{2} hours

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Express the first quantity as a percentage of second quantity $45, $120.
Pachacha [2.7K]

Answer: 37.5%

Step-by-step explanation:

Percentage = Given Quantity/Total Quantity*100

So here, it will be like: 45/120*100

                                    =0.375*100

                                    =37.5%

5 0
3 years ago
I must convert a percent into a fraction,the percent is 93%. a.k.a <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B93%7D%7B100%7D
gtnhenbr [62]
First, you put 93 over 100.
Then, you simplify the fraction. But it is in simplified form.
Answer is 93/100.
6 0
3 years ago
By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00pm positive or negative?
Ad libitum [116K]

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.​

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

6 0
3 years ago
Deborah has $56 in her bank account currently. She earns $8 per hour at her job at the local ice cream shop. Micah has $32 in hi
Scilla [17]
5 hours I did this on Plato
4 0
3 years ago
Use the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is 68 miles per​ hour, with a standard
Vladimir79 [104]

About 99.7% of vehicles whose speeds are between 59 miles per hour and 77 miles per hour.

Empirical rule states that for a normal distribution, 68% lie within one standard deviations, 95% lie within two standard deviations, and 99.7% lie within three standard deviations of the mean.

Given that mean (μ) = 68 miles per hour, standard deviation (σ) = 3 miles per hour.

68% lie within one standard deviation = (μ ± σ) = (68 ± 3) = (65, 71).

Hence 68% of the vehicle speed is between 65 miles per hour and 71 miles per hour.

95% lie within two standard deviation = (μ ± 2σ) = (68 ± 2*3) = (62, 74).

Hence 95% of the vehicle speed is between 62 miles per hour and 74 miles per hour.

99.7% lie within three standard deviation = (μ ± 3σ) = (68 ± 3*3) = (59, 77).

Hence 99.7% of the vehicle speed is between 59 miles per hour and 77 miles per hour.

Find out more at: brainly.com/question/14468516

3 0
3 years ago
Read 2 more answers
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