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Olin [163]
2 years ago
13

What are vertical angles always equal to

Mathematics
1 answer:
babymother [125]2 years ago
8 0

Answer:

Vertical angles are always equal to one another. In general, we can say that, 2 pairs of vertical angles are formed when two lines intersect.

Step-by-step explanation:

Parallel lines are lines that do not meet at any point in a plane.

Intersecting lines are straight lines that meet or crosses each other at a certain point.

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A robotics company sells robot vacuum cleaners. Since the newest model was introduced a
Svetach [21]
Answer : 2,881.2 vacuum cleaners will be sold three months from now.

Steps:
8400*0.7=5880 -> 1 month from now (It’s 0.7 because it decreases by 30% so 70% will remain)
5880*0.7= 4116 -> 2 months from now
4116*0.7= 2881.2 -> 3 months from now


*note that this solution is based on the assumption that the 30% refers to it decreases by 30% of the previous months amount of vacuum cleaners sold, and not the amount of vacuum cleaners sold this month. If it were based on the amount of vacuum cleaners sold this month, the answer would be 840. (8400*0.1)



4 0
3 years ago
What is the area of a rectangle with vertices at ​ (−6, 3) ​, ​ (−3, 6) ​ , (1, 2) , and (−2, −1) ?
PilotLPTM [1.2K]
48 units, 6 units by 8 units
5 0
4 years ago
What is 8640 minutes, in days? ​
Mashutka [201]

Answer:

8,640 Minutes = 6 Days

Step-by-step explanation:

8640 minutes/60 minutes per hr=144 hours

144 hours/24 hrs a day=6 days

7 0
3 years ago
Read 2 more answers
Find f' f(x)=sqr root(x+9), a=7<br>use the definition lim f(x+h)-f(x)/h
Romashka-Z-Leto [24]

f(x)=√(x+9)

f(x+h) =√(x+h+9)

f'(x) =  \lim_{h \to \\0} \frac{\sqrt{x+9+h}-\sqrt{x+9}}{h} = \\ \\ =    \lim_{h \to \\0} \frac{(\sqrt{x+9+h}-\sqrt{x+9})*(\sqrt{x+9+h}+\sqrt{x+9})}{h(\sqrt{x+9+h}+\sqrt{x+9})} =  \\ \\=   \lim_{h \to \\0} \frac{(\sqrt{x+9+h})^{2}-(\sqrt{x+9})^{2}}{h(\sqrt{x+9+h}+\sqrt{x+9})}= \\ \\= \lim_{n \to \\0} \frac{x+9+h-x-9}{h(\sqrt{x+9+h}+\sqrt{x+9})}=\lim_{n \to \\0} \frac{h}{h(\sqrt{x+9+h}+\sqrt{x+9})}=\lim_{n \to \\0} \frac{1}{(\sqrt{x+9+h}+\sqrt{x+9})} = \\ \\= \frac{1}{(\sqrt{x+9+0}+\sqrt{x+9})} =

=\frac{1}{(\sqrt{x+9}+\sqrt{x+9})} = \frac{1}{2\sqrt{x+9}}


f'(x)= \frac{1}{2\sqrt{x+9}}  \\ \\ f'(a)=\frac{1}{2\sqrt{a+9}}  \\ \\a=7 \\ \\f'(7)= \frac{1}{2\sqrt{7+9}} = \frac{1}{2*4} =\frac{1}{8} \\ \\f'(7)= \frac{1}{8}

3 0
3 years ago
Please Help!
aksik [14]
To solve the question we need to calculate the total circumference of the wheel plus the rim.
Total diameter will be:
d=(4+4+37+37)=82 cm
hence:
C=πd
C=3.14×82
C=257.48 cm
Thus the total rotations required to cover 95267.6 cm will be:
Rotations=95267.6/257.48
               =370 rotations

Answer: D] 370 rotations
3 0
3 years ago
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