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Vlad [161]
3 years ago
14

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

ope B does this in 43 days. What is the approximate difference in the half-lives of the isotopes?
a 3 days
b 10 days
c 13 days
d 33 days

Mathematics
2 answers:
Luden [163]3 years ago
8 0

Answer:

3 days

Step-by-step explanation:

took the test

Molodets [167]3 years ago
4 0
It should be c cause I just took the test
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How many square inches are in 60 ft.
NeTakaya
8640 square inches.
6 0
3 years ago
Help me
Korolek [52]

Answer:

GIVE ME MY RAMEN

Step-by-step explanation:

3.

add like terms

30 + 7k = 100

100-30 = 70

70 divided by 7k = 10

k = 10

4. add the z's together

2z - 6 -2 = -10

+ 6 + 2

-10 will be -2 now since we dragged the -6 and -2 to the other side

2z = -2

z = -1

5. 3.2x - 1.7x = 1.5x

1.5x + 5.5 = 10

10 would be 4.5 since we dragged 5.5 to the other side so it would be 10 - 5.5

3.2x = 5.5

x = 1.71875

6.

3/4x - 1/4x = 2/4x

14 - 3 = 11

2/4x = 11

x = 22

7 0
3 years ago
Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp
romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

\text{Distance}=\text{Speed}\times \text{Time}

\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}

\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}.

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}

\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

\text{Distance between both cars}=\sqrt{147^2+150^2}

\text{Distance between both cars}=\sqrt{21609+22500}

\text{Distance between both cars}=\sqrt{44109}

\text{Distance between both cars}=210.021427\approx 210

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0
3 years ago
Which one is the answer for these qution 4x=5(9x+2)<br> A)5/2<br> B)41/10<br> C)-10/41<br> D)10/41
stealth61 [152]
C. -10/41

First use the distributive property to get 4x = 45x + 10
Use subtraction on both sides by 10
Again use subtraction of 4x on both sides
You now have -10 = 41x
Use division to get x alone and you now have -10/41 = x
5 0
3 years ago
Choose the correct sum of the polynomials (2x3 − 5x − 1) + (4x3 + 8x + 3).
irakobra [83]
<span>(2x3 − 5x − 1) + (4x3 + 8x + 3)
=6x^3 +3x +2

answer is </span><span> b. 6x3 + 3x + 2</span>
5 0
3 years ago
Read 2 more answers
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