Please help me with this 4.7 x 10^-1 as an ordinary number

Mathematics

2 answers:

NARA [144]2 years ago

8 0

Answer:

0.47

Step-by-step explanation:

47/100

hope it helps thank you

Alexandra [31]2 years ago

3 0

Answer:

The answer is 0.47

Msmsmsmaka

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ira [324]

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How many times larger than (6 - 4) is (6 - 4) × 5?

tresset_1 [31]

Answer:

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Step-by-step explanation:

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1 year ago

Sorry to the people who were helping me earlier, but I actually don't get this one. I really need help if anyone could help with

Fed [463]

7/12
12/7
1`2/7
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a reciprocal you just flip the fraction

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2 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,